COMPARISION OF EMF , principle of potentiometer GSEB std 11 & 12 Physics practical

Comparision of emf

COMPARISION OF EMF 

Experiment  6(a)

AIM :-

Two cells EA and EB, a potentiometer and necessary components are given. Connect E_A and E_B one after the other and find the ratio of their emfs.

PRINCIPLE :

It works on the principle of potentiometer.

APPARATUS:

A resistive wire, Laclanche cell, Daniel cell, a main battery, two rheostats, Potentiometer, jokey, key, Galvanometer, Resistance box,

Apparatus for comparision of EMF

Adjust all apparatus as per shown here

Line Diagram fof Comparision of EMF

Line Diagram fof Comparision of EMF

Comparison of EMF Practical

Comparison of EMF Practica

Comparison of EMF Practica

Comparison of EMF Practical Procedure

Calculation table for Comparison of EMF

Experiment  6(b)

AIM :-

Verify the results by joining both the cells in helping and opposing conditions.

APPARATUS :

A resistive wire ( ~ 400  cm length of uniform cross-section fixed on a wooden board, two primary cells ( e.g. Laclanche cell and Daniel cell ), a main battery ( 0 – 12 V ) ( the voltage of this battery must be more than E_A + E_B), two rheostats Rh₁(o - 25W) and Rh₂ ( 0 - 500W)

Apparatus of Comparision of EMF (ii)

PRECAUTIONS

1    First decide from experiment :6(a), which cell has larger emf. Call that cell E_A and the other cell E_B

2      Here, Rh₁ should be having smaller resistance than Rh₂.

3      The value of Rh₁ should be the same while taking observations for EA and E_B.

            For the observation of each set of helping-opposing conditions, the resistance in Rh₁ should not be changed.

Line diagram Comparision of EMF (Helping Connection)

Comparision of EMF Practical

Comparision of EMF Practical

Comparision of EMF Practical

Result :

1  By connecting E_A and E_B separately :  E_A / E_B = ……………

2   By connecting E_A and E_B in helping and opposing conditions : EA / EB = ……..